Segment Trees
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What is Segment Trees?
A Segment Tree is a data structure designed for efficient processing of range queries and updates on array elements. In a situation where you have an array and you need to execute several types of queries including updating array elements and computing sum or minimum or maximum of elements in a given range, segment trees could be a great choice. The tree itself is a height-balanced binary tree and is filled with data from the input array. The leaves of the Segment Tree contain the array elements, while the internal nodes store information needed for processing the query, often the sum, minimum, or maximum of the elements represented by their child nodes. Efficient implementation of segment trees can achieve query and update operations in logarithmic time.
More in stage 11: Advanced Data Structures
- Advanced Data Structures
- Trie
- Fenwick Trees
- Disjoint Set (Union-Find)
- Suffix Trees and Arrays
- Binary Trees
- Tree Traversal
- Search Algorithms
- Binary Search Trees
- In-Order Traversal
- Breadth First Search
- AVL Trees
- Pre-Order Traversal
- Depth First Search
- B-Trees
- Heap
- Post-Order Traversal
- Search Algorithms
- Breadth First Search
- Depth First Search
- Shortest Path Algorithms
- Dijkstra's Algorithm
- Bellman-Ford Algoritm
- A* Algorithm
- Minimum Spanning Tree
- Prim's Algorithm
- Kruskal's Algorithm
Segment Trees: common questions
Can I learn Segment Trees in Hindi?
This lesson is written in English. Once you sign in, open it in the interactive course and ask the AI tutor to explain Segment Trees in Hindi or Hinglish. The tutor answers from this lesson’s own text, so it stays on the syllabus, and it runs on your own Google, OpenAI or Anthropic key.
Is this Segment Trees tutorial for beginners?
It is lesson 54 of 107 in the free Data Structures & Algorithms roadmap, in stage 11, Advanced Data Structures. If you are new to Data Structures & Algorithms, start from stage 1 and come back here in order; if you already know the earlier stages, this lesson stands on its own.